6+2(3x-2)=4(x+1)

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Solution for 6+2(3x-2)=4(x+1) equation: 



6+2(3x-2)=4(x+1)

We move all terms to the left:

6+2(3x-2)-(4(x+1))=0

We multiply parentheses

6x-(4(x+1))-4+6=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

6x-(4x+4)+2=0

We get rid of parentheses

6x-4x-4+2=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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