6+2(3w-2)=4(1+w)

Solution for 6+2(3w-2)=4(1+w) equation:

6+2(3w-2)=4(1+w)

We move all terms to the left:

6+2(3w-2)-(4(1+w))=0

We add all the numbers together, and all the variables

2(3w-2)-(4(w+1))+6=0

We multiply parentheses

6w-(4(w+1))-4+6=0


We calculate terms in parentheses: -(4(w+1)), so:

4(w+1)

We multiply parentheses

4w+4

Back to the equation:

-(4w+4)


We add all the numbers together, and all the variables

6w-(4w+4)+2=0

We get rid of parentheses

6w-4w-4+2=0

We add all the numbers together, and all the variables

2w-2=0

We move all terms containing w to the left, all other terms to the right

2w=2

w=2/2

w=1