6+2(3j-2)=4(1=j)

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Solution for 6+2(3j-2)=4(1=j) equation: 



6+2(3j-2)=4(1=j)

We move all terms to the left:

6+2(3j-2)-(4(1)=0

We add all the numbers together, and all the variables

2(3j-2)=0

We multiply parentheses

6j-4=0

We move all terms containing j to the left, all other terms to the right

6j=4

j=4/6

j=2/3

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