6+2(3j-2)=4(1+f)

Solution for 6+2(3j-2)=4(1+f) equation:

Simplifying
6 + 2(3j + -2) = 4(1 + f)

Reorder the terms:
6 + 2(-2 + 3j) = 4(1 + f)
6 + (-2 * 2 + 3j * 2) = 4(1 + f)
6 + (-4 + 6j) = 4(1 + f)

Combine like terms: 6 + -4 = 2
2 + 6j = 4(1 + f)
2 + 6j = (1 * 4 + f * 4)
2 + 6j = (4 + 4f)

Solving
2 + 6j = 4 + 4f

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 6j = 4 + -2 + 4f

Combine like terms: 2 + -2 = 0
0 + 6j = 4 + -2 + 4f
6j = 4 + -2 + 4f

Combine like terms: 4 + -2 = 2
6j = 2 + 4f

Divide each side by '6'.
j = 0.3333333333 + 0.6666666667f

Simplifying
j = 0.3333333333 + 0.6666666667f