6+1x+-15x2=12+-10x

Solution for 6+1x+-15x2=12+-10x equation:

6+1x+-15x^2=12+-10x

We move all terms to the left:

6+1x+-15x^2-(12+-10x)=0

We add all the numbers together, and all the variables

-15x^2+1x-(-10x)+6+=0

We add all the numbers together, and all the variables

-15x^2+x-(-10x)=0

We get rid of parentheses

-15x^2+x+10x=0

We add all the numbers together, and all the variables

-15x^2+11x=0

a = -15; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·(-15)·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*-15}=\frac{-22}{-30}
=11/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*-15}=\frac{0}{-30}
=0
$