6+1=2(3x-2)+5

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Solution for 6+1=2(3x-2)+5 equation: 



6+1=2(3x-2)+5

We move all terms to the left:

6+1-(2(3x-2)+5)=0

We add all the numbers together, and all the variables

-(2(3x-2)+5)+7=0



We calculate terms in parentheses: -(2(3x-2)+5), so:

2(3x-2)+5

We multiply parentheses

6x-4+5

We add all the numbers together, and all the variables

6x+1

Back to the equation:

-(6x+1)



We get rid of parentheses

-6x-1+7=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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