6+-2(1x+-2)=6(1x+3)

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Solution for 6+-2(1x+-2)=6(1x+3) equation: 



6+-2(1x+-2)=6(1x+3)

We move all terms to the left:

6+-2(1x+-2)-(6(1x+3))=0

We add all the numbers together, and all the variables

-2(x-2)-(6(x+3))+6+=0

We add all the numbers together, and all the variables

-2(x-2)-(6(x+3))=0

We multiply parentheses

-2x-(6(x+3))+4=0



We calculate terms in parentheses: -(6(x+3)), so:

6(x+3)

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

-2x-6x-18+4=0

We add all the numbers together, and all the variables

-8x-14=0

We move all terms containing x to the left, all other terms to the right

-8x=14

x=14/-8

x=-1+3/4

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