6+(x+8)=4+(3x-12)

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Solution for 6+(x+8)=4+(3x-12) equation: 



6+(x+8)=4+(3x-12)

We move all terms to the left:

6+(x+8)-(4+(3x-12))=0

We get rid of parentheses

x-(4+(3x-12))+8+6=0



We calculate terms in parentheses: -(4+(3x-12)), so:

4+(3x-12)

determiningTheFunctionDomain
(3x-12)+4

We get rid of parentheses

3x-12+4

We add all the numbers together, and all the variables

3x-8

Back to the equation:

-(3x-8)



We add all the numbers together, and all the variables

x-(3x-8)+14=0

We get rid of parentheses

x-3x+8+14=0

We add all the numbers together, and all the variables

-2x+22=0

We move all terms containing x to the left, all other terms to the right

-2x=-22

x=-22/-2

x=+11

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