6+(5/(u-2))=4/(u+1)

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Solution for 6+(5/(u-2))=4/(u+1) equation: 


D( u )

u+1 = 0

u-2 = 0

u+1 = 0

u+1 = 0

u+1 = 0 // - 1

u = -1

u-2 = 0

u-2 = 0

u-2 = 0 // + 2

u = 2

u in (-oo:-1) U (-1:2) U (2:+oo)

5/(u-2)+6 = 4/(u+1) // - 4/(u+1)

5/(u-2)-(4/(u+1))+6 = 0

5/(u-2)-4*(u+1)^-1+6 = 0

5/(u-2)-4/(u+1)+6 = 0

(5*(u+1))/((u-2)*(u+1))+(-4*(u-2))/((u-2)*(u+1))+(6*(u-2)*(u+1))/((u-2)*(u+1)) = 0

5*(u+1)-4*(u-2)+6*(u-2)*(u+1) = 0

6*u^2+u-6*u-12+13 = 0

6*u^2-5*u+1 = 0

6*u^2-5*u+1 = 0

6*u^2-5*u+1 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

u = (1^(1/2)+5)/(2*6) or u = (5-1^(1/2))/(2*6)

u = 1/2 or u = 1/3

(u-1/3)*(u-1/2) = 0

((u-1/3)*(u-1/2))/((u-2)*(u+1)) = 0

((u-1/3)*(u-1/2))/((u-2)*(u+1)) = 0 // * (u-2)*(u+1)

(u-1/3)*(u-1/2) = 0

( u-1/2 )

u-1/2 = 0 // + 1/2

u = 1/2

( u-1/3 )

u-1/3 = 0 // + 1/3

u = 1/3

u in { 1/2, 1/3 }

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