6+(4-m)=8(3m+m)

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Solution for 6+(4-m)=8(3m+m) equation: 



6+(4-m)=8(3m+m)

We move all terms to the left:

6+(4-m)-(8(3m+m))=0

We add all the numbers together, and all the variables

(-1m+4)-(8(+4m))+6=0

We get rid of parentheses

-1m-(8(+4m))+4+6=0



We calculate terms in parentheses: -(8(+4m)), so:

8(+4m)

We multiply parentheses

32m

Back to the equation:

-(32m)



We add all the numbers together, and all the variables

-33m+10=0

We move all terms containing m to the left, all other terms to the right

-33m=-10

m=-10/-33

m=10/33

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