6+(4+x)=8x-2(3x+5)

Solution for 6+(4+x)=8x-2(3x+5) equation:

6+(4+x)=8x-2(3x+5)

We move all terms to the left:

6+(4+x)-(8x-2(3x+5))=0

We add all the numbers together, and all the variables

(x+4)-(8x-2(3x+5))+6=0

We get rid of parentheses

x-(8x-2(3x+5))+4+6=0


We calculate terms in parentheses: -(8x-2(3x+5)), so:

8x-2(3x+5)

We multiply parentheses

8x-6x-10

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)


We add all the numbers together, and all the variables

x-(2x-10)+10=0

We get rid of parentheses

x-2x+10+10=0

We add all the numbers together, and all the variables

-1x+20=0

We move all terms containing x to the left, all other terms to the right

-x=-20

x=-20/-1

x=+20