6+(3z+1)/8=11

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Solution for 6+(3z+1)/8=11 equation: 



6+(3z+1)/8=11

We move all terms to the left:

6+(3z+1)/8-(11)=0

We add all the numbers together, and all the variables

(3z+1)/8-5=0

We multiply all the terms by the denominator


(3z+1)-5*8=0

We add all the numbers together, and all the variables

(3z+1)-40=0

We get rid of parentheses

3z+1-40=0

We add all the numbers together, and all the variables

3z-39=0

We move all terms containing z to the left, all other terms to the right

3z=39

z=39/3

z=13

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