6+(3y+4)=17

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Solution for 6+(3y+4)=17 equation: 



6+(3y+4)=17

We move all terms to the left:

6+(3y+4)-(17)=0

We add all the numbers together, and all the variables

(3y+4)-11=0

We get rid of parentheses

3y+4-11=0

We add all the numbers together, and all the variables

3y-7=0

We move all terms containing y to the left, all other terms to the right

3y=7

y=7/3

y=2+1/3

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