6+(1)/(3)(x-9)=(1)/(2)(2-x)

Solution for 6+(1)/(3)(x-9)=(1)/(2)(2-x) equation:

6+(1)/(3)(x-9)=(1)/(2)(2-x)

We move all terms to the left:

6+(1)/(3)(x-9)-((1)/(2)(2-x))=0


Domain of the equation: 3(x-9)!=0

x∈R



Domain of the equation: 2(2-x))!=0

x∈R


We add all the numbers together, and all the variables

1/3(x-9)-(1/2(-1x+2))+6=0

We calculate fractions


(2x(-)/(3(x-9)*2(-1x+2)))+(-3xx/(3(x-9)*2(-1x+2)))+6=0


We calculate terms in parentheses: +(2x(-)/(3(x-9)*2(-1x+2))), so:

2x(-)/(3(x-9)*2(-1x+2))

We add all the numbers together, and all the variables

2x0/(3(x-9)*2(-1x+2))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)



We calculate terms in parentheses: +(-3xx/(3(x-9)*2(-1x+2))), so:

-3xx/(3(x-9)*2(-1x+2))

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

2x-3xx+6=0

We move all terms containing x to the left, all other terms to the right

2x-3xx=-6