6(z-10)=3z

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Solution for 6(z-10)=3z equation: 



6(z-10)=3z

We move all terms to the left:

6(z-10)-(3z)=0

We add all the numbers together, and all the variables

-3z+6(z-10)=0

We multiply parentheses

-3z+6z-60=0

We add all the numbers together, and all the variables

3z-60=0

We move all terms containing z to the left, all other terms to the right

3z=60

z=60/3

z=20

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