6(z+6)=3(2z+12)

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Solution for 6(z+6)=3(2z+12) equation: 


Simplifying
6(z + 6) = 3(2z + 12)

Reorder the terms:
6(6 + z) = 3(2z + 12)
(6 * 6 + z * 6) = 3(2z + 12)
(36 + 6z) = 3(2z + 12)

Reorder the terms:
36 + 6z = 3(12 + 2z)
36 + 6z = (12 * 3 + 2z * 3)
36 + 6z = (36 + 6z)

Add '-36' to each side of the equation.
36 + -36 + 6z = 36 + -36 + 6z

Combine like terms: 36 + -36 = 0
0 + 6z = 36 + -36 + 6z
6z = 36 + -36 + 6z

Combine like terms: 36 + -36 = 0
6z = 0 + 6z
6z = 6z

Add '-6z' to each side of the equation.
6z + -6z = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 6z + -6z

Combine like terms: 6z + -6z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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