6(z+3)-5(3z+2)=2(27-9)

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Solution for 6(z+3)-5(3z+2)=2(27-9) equation:


Simplifying
6(z + 3) + -5(3z + 2) = 2(27 + -9)

Reorder the terms:
6(3 + z) + -5(3z + 2) = 2(27 + -9)
(3 * 6 + z * 6) + -5(3z + 2) = 2(27 + -9)
(18 + 6z) + -5(3z + 2) = 2(27 + -9)

Reorder the terms:
18 + 6z + -5(2 + 3z) = 2(27 + -9)
18 + 6z + (2 * -5 + 3z * -5) = 2(27 + -9)
18 + 6z + (-10 + -15z) = 2(27 + -9)

Reorder the terms:
18 + -10 + 6z + -15z = 2(27 + -9)

Combine like terms: 18 + -10 = 8
8 + 6z + -15z = 2(27 + -9)

Combine like terms: 6z + -15z = -9z
8 + -9z = 2(27 + -9)

Combine like terms: 27 + -9 = 18
8 + -9z = 2(18)

Multiply 2 * 18
8 + -9z = 36

Solving
8 + -9z = 36

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -9z = 36 + -8

Combine like terms: 8 + -8 = 0
0 + -9z = 36 + -8
-9z = 36 + -8

Combine like terms: 36 + -8 = 28
-9z = 28

Divide each side by '-9'.
z = -3.111111111

Simplifying
z = -3.111111111

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