6(z+2)=3(z+1)-9

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Solution for 6(z+2)=3(z+1)-9 equation:


Simplifying
6(z + 2) = 3(z + 1) + -9

Reorder the terms:
6(2 + z) = 3(z + 1) + -9
(2 * 6 + z * 6) = 3(z + 1) + -9
(12 + 6z) = 3(z + 1) + -9

Reorder the terms:
12 + 6z = 3(1 + z) + -9
12 + 6z = (1 * 3 + z * 3) + -9
12 + 6z = (3 + 3z) + -9

Reorder the terms:
12 + 6z = 3 + -9 + 3z

Combine like terms: 3 + -9 = -6
12 + 6z = -6 + 3z

Solving
12 + 6z = -6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
12 + 6z + -3z = -6 + 3z + -3z

Combine like terms: 6z + -3z = 3z
12 + 3z = -6 + 3z + -3z

Combine like terms: 3z + -3z = 0
12 + 3z = -6 + 0
12 + 3z = -6

Add '-12' to each side of the equation.
12 + -12 + 3z = -6 + -12

Combine like terms: 12 + -12 = 0
0 + 3z = -6 + -12
3z = -6 + -12

Combine like terms: -6 + -12 = -18
3z = -18

Divide each side by '3'.
z = -6

Simplifying
z = -6

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