6(z+1)=5(z-7)+z

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Solution for 6(z+1)=5(z-7)+z equation:


Simplifying
6(z + 1) = 5(z + -7) + z

Reorder the terms:
6(1 + z) = 5(z + -7) + z
(1 * 6 + z * 6) = 5(z + -7) + z
(6 + 6z) = 5(z + -7) + z

Reorder the terms:
6 + 6z = 5(-7 + z) + z
6 + 6z = (-7 * 5 + z * 5) + z
6 + 6z = (-35 + 5z) + z

Combine like terms: 5z + z = 6z
6 + 6z = -35 + 6z

Add '-6z' to each side of the equation.
6 + 6z + -6z = -35 + 6z + -6z

Combine like terms: 6z + -6z = 0
6 + 0 = -35 + 6z + -6z
6 = -35 + 6z + -6z

Combine like terms: 6z + -6z = 0
6 = -35 + 0
6 = -35

Solving
6 = -35

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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