6(z+1)=4+5(z+1)

Solution for 6(z+1)=4+5(z+1) equation:

Simplifying
6(z + 1) = 4 + 5(z + 1)

Reorder the terms:
6(1 + z) = 4 + 5(z + 1)
(1 * 6 + z * 6) = 4 + 5(z + 1)
(6 + 6z) = 4 + 5(z + 1)

Reorder the terms:
6 + 6z = 4 + 5(1 + z)
6 + 6z = 4 + (1 * 5 + z * 5)
6 + 6z = 4 + (5 + 5z)

Combine like terms: 4 + 5 = 9
6 + 6z = 9 + 5z

Solving
6 + 6z = 9 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
6 + 6z + -5z = 9 + 5z + -5z

Combine like terms: 6z + -5z = 1z
6 + 1z = 9 + 5z + -5z

Combine like terms: 5z + -5z = 0
6 + 1z = 9 + 0
6 + 1z = 9

Add '-6' to each side of the equation.
6 + -6 + 1z = 9 + -6

Combine like terms: 6 + -6 = 0
0 + 1z = 9 + -6
1z = 9 + -6

Combine like terms: 9 + -6 = 3
1z = 3

Divide each side by '1'.
z = 3

Simplifying
z = 3