6(y-5)=3(y-1)

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Solution for 6(y-5)=3(y-1) equation: 



6(y-5)=3(y-1)

We move all terms to the left:

6(y-5)-(3(y-1))=0

We multiply parentheses

6y-(3(y-1))-30=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

6y-3y+3-30=0

We add all the numbers together, and all the variables

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9

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