6(y-5)=27

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Solution for 6(y-5)=27 equation: 



6(y-5)=27

We move all terms to the left:

6(y-5)-(27)=0

We multiply parentheses

6y-30-27=0

We add all the numbers together, and all the variables

6y-57=0

We move all terms containing y to the left, all other terms to the right

6y=57

y=57/6

y=9+1/2

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