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6(y-5)=2(5y-1)
We move all terms to the left:
6(y-5)-(2(5y-1))=0
We multiply parentheses
6y-(2(5y-1))-30=0
We calculate terms in parentheses: -(2(5y-1)), so:We get rid of parentheses
2(5y-1)
We multiply parentheses
10y-2
Back to the equation:
-(10y-2)
6y-10y+2-30=0
We add all the numbers together, and all the variables
-4y-28=0
We move all terms containing y to the left, all other terms to the right
-4y=28
y=28/-4
y=-7
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