6(y-5)=2(10-3y)

Solution for 6(y-5)=2(10-3y) equation:

6(y-5)=2(10-3y)

We move all terms to the left:

6(y-5)-(2(10-3y))=0

We add all the numbers together, and all the variables

6(y-5)-(2(-3y+10))=0

We multiply parentheses

6y-(2(-3y+10))-30=0


We calculate terms in parentheses: -(2(-3y+10)), so:

2(-3y+10)

We multiply parentheses

-6y+20

Back to the equation:

-(-6y+20)


We get rid of parentheses

6y+6y-20-30=0

We add all the numbers together, and all the variables

12y-50=0

We move all terms containing y to the left, all other terms to the right

12y=50

y=50/12

y=4+1/6