6(y-4)-5=-3(-8y+5)-6y

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Solution for 6(y-4)-5=-3(-8y+5)-6y equation: 



6(y-4)-5=-3(-8y+5)-6y

We move all terms to the left:

6(y-4)-5-(-3(-8y+5)-6y)=0

We multiply parentheses

6y-(-3(-8y+5)-6y)-24-5=0



We calculate terms in parentheses: -(-3(-8y+5)-6y), so:

-3(-8y+5)-6y

We add all the numbers together, and all the variables

-6y-3(-8y+5)

We multiply parentheses

-6y+24y-15

We add all the numbers together, and all the variables

18y-15

Back to the equation:

-(18y-15)



We add all the numbers together, and all the variables

6y-(18y-15)-29=0

We get rid of parentheses

6y-18y+15-29=0

We add all the numbers together, and all the variables

-12y-14=0

We move all terms containing y to the left, all other terms to the right

-12y=14

y=14/-12

y=-1+1/6

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