6(y-4)-4(5y+7)=3(y-2)-4(2y+1)

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Solution for 6(y-4)-4(5y+7)=3(y-2)-4(2y+1) equation: 



6(y-4)-4(5y+7)=3(y-2)-4(2y+1)

We move all terms to the left:

6(y-4)-4(5y+7)-(3(y-2)-4(2y+1))=0

We multiply parentheses

6y-20y-(3(y-2)-4(2y+1))-24-28=0



We calculate terms in parentheses: -(3(y-2)-4(2y+1)), so:

3(y-2)-4(2y+1)

We multiply parentheses

3y-8y-6-4

We add all the numbers together, and all the variables

-5y-10

Back to the equation:

-(-5y-10)



We add all the numbers together, and all the variables

-14y-(-5y-10)-52=0

We get rid of parentheses

-14y+5y+10-52=0

We add all the numbers together, and all the variables

-9y-42=0

We move all terms containing y to the left, all other terms to the right

-9y=42

y=42/-9

y=-4+2/3

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