6(y-3)+3=7-(2-y)

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Solution for 6(y-3)+3=7-(2-y) equation: 



6(y-3)+3=7-(2-y)

We move all terms to the left:

6(y-3)+3-(7-(2-y))=0

We add all the numbers together, and all the variables

6(y-3)-(7-(-1y+2))+3=0

We multiply parentheses

6y-(7-(-1y+2))-18+3=0



We calculate terms in parentheses: -(7-(-1y+2)), so:

7-(-1y+2)

determiningTheFunctionDomain
-(-1y+2)+7

We get rid of parentheses

1y-2+7

We add all the numbers together, and all the variables

y+5

Back to the equation:

-(y+5)



We add all the numbers together, and all the variables

6y-(y+5)-15=0

We get rid of parentheses

6y-y-5-15=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4

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