6(y-3)+10=2(3x-4)

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Solution for 6(y-3)+10=2(3x-4) equation:


Simplifying
6(y + -3) + 10 = 2(3x + -4)

Reorder the terms:
6(-3 + y) + 10 = 2(3x + -4)
(-3 * 6 + y * 6) + 10 = 2(3x + -4)
(-18 + 6y) + 10 = 2(3x + -4)

Reorder the terms:
-18 + 10 + 6y = 2(3x + -4)

Combine like terms: -18 + 10 = -8
-8 + 6y = 2(3x + -4)

Reorder the terms:
-8 + 6y = 2(-4 + 3x)
-8 + 6y = (-4 * 2 + 3x * 2)
-8 + 6y = (-8 + 6x)

Add '8' to each side of the equation.
-8 + 8 + 6y = -8 + 8 + 6x

Combine like terms: -8 + 8 = 0
0 + 6y = -8 + 8 + 6x
6y = -8 + 8 + 6x

Combine like terms: -8 + 8 = 0
6y = 0 + 6x
6y = 6x

Solving
6y = 6x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '6'.
y = x

Simplifying
y = x

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