6(y-2)=5y+1-2(-5y-1)

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Solution for 6(y-2)=5y+1-2(-5y-1) equation: 



6(y-2)=5y+1-2(-5y-1)

We move all terms to the left:

6(y-2)-(5y+1-2(-5y-1))=0

We multiply parentheses

6y-(5y+1-2(-5y-1))-12=0



We calculate terms in parentheses: -(5y+1-2(-5y-1)), so:

5y+1-2(-5y-1)

determiningTheFunctionDomain
5y-2(-5y-1)+1

We multiply parentheses

5y+10y+2+1

We add all the numbers together, and all the variables

15y+3

Back to the equation:

-(15y+3)



We get rid of parentheses

6y-15y-3-12=0

We add all the numbers together, and all the variables

-9y-15=0

We move all terms containing y to the left, all other terms to the right

-9y=15

y=15/-9

y=-1+2/3

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