6(y-2)-5y=4(y+3)-4(y-1)

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Solution for 6(y-2)-5y=4(y+3)-4(y-1) equation: 



6(y-2)-5y=4(y+3)-4(y-1)

We move all terms to the left:

6(y-2)-5y-(4(y+3)-4(y-1))=0

We add all the numbers together, and all the variables

-5y+6(y-2)-(4(y+3)-4(y-1))=0

We multiply parentheses

-5y+6y-(4(y+3)-4(y-1))-12=0



We calculate terms in parentheses: -(4(y+3)-4(y-1)), so:

4(y+3)-4(y-1)

We multiply parentheses

4y-4y+12+4

We add all the numbers together, and all the variables

16

Back to the equation:

-(16)



We add all the numbers together, and all the variables

y-28=0

We move all terms containing y to the left, all other terms to the right

y=28

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