6(y-2)+3=21+2(y-1)

Solution for 6(y-2)+3=21+2(y-1) equation:

6(y-2)+3=21+2(y-1)

We move all terms to the left:

6(y-2)+3-(21+2(y-1))=0

We multiply parentheses

6y-(21+2(y-1))-12+3=0


We calculate terms in parentheses: -(21+2(y-1)), so:

21+2(y-1)

determiningTheFunctionDomain
2(y-1)+21

We multiply parentheses

2y-2+21

We add all the numbers together, and all the variables

2y+19

Back to the equation:

-(2y+19)


We add all the numbers together, and all the variables

6y-(2y+19)-9=0

We get rid of parentheses

6y-2y-19-9=0

We add all the numbers together, and all the variables

4y-28=0

We move all terms containing y to the left, all other terms to the right

4y=28

y=28/4

y=7