6(y-1)-2(y+2)=6

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Solution for 6(y-1)-2(y+2)=6 equation: 



6(y-1)-2(y+2)=6

We move all terms to the left:

6(y-1)-2(y+2)-(6)=0

We multiply parentheses

6y-2y-6-4-6=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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