6(y+4)=42y=

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Solution for 6(y+4)=42y= equation: 



6(y+4)=42y=

We move all terms to the left:

6(y+4)-(42y)=0

We add all the numbers together, and all the variables

-42y+6(y+4)=0

We multiply parentheses

-42y+6y+24=0

We add all the numbers together, and all the variables

-36y+24=0

We move all terms containing y to the left, all other terms to the right

-36y=-24

y=-24/-36

y=2/3

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