6(y+4)-4=y-9(3y+2)

Solution for 6(y+4)-4=y-9(3y+2) equation:

6(y+4)-4=y-9(3y+2)

We move all terms to the left:

6(y+4)-4-(y-9(3y+2))=0

We multiply parentheses

6y-(y-9(3y+2))+24-4=0


We calculate terms in parentheses: -(y-9(3y+2)), so:

y-9(3y+2)

We multiply parentheses

y-27y-18

We add all the numbers together, and all the variables

-26y-18

Back to the equation:

-(-26y-18)


We add all the numbers together, and all the variables

6y-(-26y-18)+20=0

We get rid of parentheses

6y+26y+18+20=0

We add all the numbers together, and all the variables

32y+38=0

We move all terms containing y to the left, all other terms to the right

32y=-38

y=-38/32

y=-1+3/16