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6(y+3)=-5(3y-2)+5y
We move all terms to the left:
6(y+3)-(-5(3y-2)+5y)=0
We multiply parentheses
6y-(-5(3y-2)+5y)+18=0
We calculate terms in parentheses: -(-5(3y-2)+5y), so:We get rid of parentheses
-5(3y-2)+5y
We add all the numbers together, and all the variables
5y-5(3y-2)
We multiply parentheses
5y-15y+10
We add all the numbers together, and all the variables
-10y+10
Back to the equation:
-(-10y+10)
6y+10y-10+18=0
We add all the numbers together, and all the variables
16y+8=0
We move all terms containing y to the left, all other terms to the right
16y=-8
y=-8/16
y=-1/2
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