6(y+3)-11=-y+2

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Solution for 6(y+3)-11=-y+2 equation: 



6(y+3)-11=-y+2

We move all terms to the left:

6(y+3)-11-(-y+2)=0

We add all the numbers together, and all the variables

6(y+3)-(-1y+2)-11=0

We multiply parentheses

6y-(-1y+2)+18-11=0

We get rid of parentheses

6y+1y-2+18-11=0

We add all the numbers together, and all the variables

7y+5=0

We move all terms containing y to the left, all other terms to the right

7y=-5

y=-5/7

y=-5/7

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