6(y+3)+y=3(y+5)-4

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Solution for 6(y+3)+y=3(y+5)-4 equation: 



6(y+3)+y=3(y+5)-4

We move all terms to the left:

6(y+3)+y-(3(y+5)-4)=0

We add all the numbers together, and all the variables

y+6(y+3)-(3(y+5)-4)=0

We multiply parentheses

y+6y-(3(y+5)-4)+18=0



We calculate terms in parentheses: -(3(y+5)-4), so:

3(y+5)-4

We multiply parentheses

3y+15-4

We add all the numbers together, and all the variables

3y+11

Back to the equation:

-(3y+11)



We add all the numbers together, and all the variables

7y-(3y+11)+18=0

We get rid of parentheses

7y-3y-11+18=0

We add all the numbers together, and all the variables

4y+7=0

We move all terms containing y to the left, all other terms to the right

4y=-7

y=-7/4

y=-1+3/4

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