6(y+2)=5y-(3y-1)

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Solution for 6(y+2)=5y-(3y-1) equation:



6(y+2)=5y-(3y-1)
We move all terms to the left:
6(y+2)-(5y-(3y-1))=0
We multiply parentheses
6y-(5y-(3y-1))+12=0
We calculate terms in parentheses: -(5y-(3y-1)), so:
5y-(3y-1)
We get rid of parentheses
5y-3y+1
We add all the numbers together, and all the variables
2y+1
Back to the equation:
-(2y+1)
We get rid of parentheses
6y-2y-1+12=0
We add all the numbers together, and all the variables
4y+11=0
We move all terms containing y to the left, all other terms to the right
4y=-11
y=-11/4
y=-2+3/4

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