6(y+2)=3(y-1)

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Solution for 6(y+2)=3(y-1) equation: 



6(y+2)=3(y-1)

We move all terms to the left:

6(y+2)-(3(y-1))=0

We multiply parentheses

6y-(3(y-1))+12=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

6y-3y+3+12=0

We add all the numbers together, and all the variables

3y+15=0

We move all terms containing y to the left, all other terms to the right

3y=-15

y=-15/3

y=-5

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