6(y+2)=-3(2y-6)+2y

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Solution for 6(y+2)=-3(2y-6)+2y equation: 



6(y+2)=-3(2y-6)+2y

We move all terms to the left:

6(y+2)-(-3(2y-6)+2y)=0

We multiply parentheses

6y-(-3(2y-6)+2y)+12=0



We calculate terms in parentheses: -(-3(2y-6)+2y), so:

-3(2y-6)+2y

We add all the numbers together, and all the variables

2y-3(2y-6)

We multiply parentheses

2y-6y+18

We add all the numbers together, and all the variables

-4y+18

Back to the equation:

-(-4y+18)



We get rid of parentheses

6y+4y-18+12=0

We add all the numbers together, and all the variables

10y-6=0

We move all terms containing y to the left, all other terms to the right

10y=6

y=6/10

y=3/5

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