6(y+2)-8y=-4

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Solution for 6(y+2)-8y=-4 equation: 



6(y+2)-8y=-4

We move all terms to the left:

6(y+2)-8y-(-4)=0

We add all the numbers together, and all the variables

-8y+6(y+2)+4=0

We multiply parentheses

-8y+6y+12+4=0

We add all the numbers together, and all the variables

-2y+16=0

We move all terms containing y to the left, all other terms to the right

-2y=-16

y=-16/-2

y=+8

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