6(y+2)-4y=10

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Solution for 6(y+2)-4y=10 equation: 



6(y+2)-4y=10

We move all terms to the left:

6(y+2)-4y-(10)=0

We add all the numbers together, and all the variables

-4y+6(y+2)-10=0

We multiply parentheses

-4y+6y+12-10=0

We add all the numbers together, and all the variables

2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1

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