6(y+1)=8y+4

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Solution for 6(y+1)=8y+4 equation: 



6(y+1)=8y+4

We move all terms to the left:

6(y+1)-(8y+4)=0

We multiply parentheses

6y-(8y+4)+6=0

We get rid of parentheses

6y-8y-4+6=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1

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