6(y+1)=8y

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Solution for 6(y+1)=8y equation: 



6(y+1)=8y

We move all terms to the left:

6(y+1)-(8y)=0

We add all the numbers together, and all the variables

-8y+6(y+1)=0

We multiply parentheses

-8y+6y+6=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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