6(x2-2)+1-16+x=

Solution for 6(x2-2)+1-16+x= equation:

6(x2-2)+1-16+x=

We move all terms to the left:

6(x2-2)+1-16+x-()=0

We add all the numbers together, and all the variables

6(+x^2-2)+x+1-16-()=0

We add all the numbers together, and all the variables

6(+x^2-2)+x=0

We multiply parentheses

6x^2+x-12=0

a = 6; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·6·(-12)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-17}{2*6}=\frac{-18}{12}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+17}{2*6}=\frac{16}{12}
=1+1/3
$