6(x2+2x+1)=0

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Solution for 6(x2+2x+1)=0 equation: 



6(x2+2x+1)=0

We add all the numbers together, and all the variables

6(+x^2+2x+1)=0

We multiply parentheses

6x^2+12x+6=0

a = 6; b = 12; c = +6;
Δ = b2-4ac
Δ = 122-4·6·6
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{12}=-1$

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