6(x2+2x)=2(3x2+12)

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Solution for 6(x2+2x)=2(3x2+12) equation: 



6(x2+2x)=2(3x^2+12)

We move all terms to the left:

6(x2+2x)-(2(3x^2+12))=0

We add all the numbers together, and all the variables

6(+x^2+2x)-(2(3x^2+12))=0

We multiply parentheses

6x^2+12x-(2(3x^2+12))=0



We calculate terms in parentheses: -(2(3x^2+12)), so:

2(3x^2+12)

We multiply parentheses

6x^2+24

Back to the equation:

-(6x^2+24)



We get rid of parentheses

6x^2-6x^2+12x-24=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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