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6(x/3+5)-2=3(2x+10)=10
We move all terms to the left:
6(x/3+5)-2-(3(2x+10))=0
We multiply parentheses
6x-(3(2x+10))+30-2=0
We calculate terms in parentheses: -(3(2x+10)), so:We add all the numbers together, and all the variables
3(2x+10)
We multiply parentheses
6x+30
Back to the equation:
-(6x+30)
6x-(6x+30)+28=0
We get rid of parentheses
6x-6x-30+28=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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