6(x-7)-4(x+2)=1

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Solution for 6(x-7)-4(x+2)=1 equation: 



6(x-7)-4(x+2)=1

We move all terms to the left:

6(x-7)-4(x+2)-(1)=0

We multiply parentheses

6x-4x-42-8-1=0

We add all the numbers together, and all the variables

2x-51=0

We move all terms containing x to the left, all other terms to the right

2x=51

x=51/2

x=25+1/2

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