6(x-6)=4(x-4)-3

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Solution for 6(x-6)=4(x-4)-3 equation: 



6(x-6)=4(x-4)-3

We move all terms to the left:

6(x-6)-(4(x-4)-3)=0

We multiply parentheses

6x-(4(x-4)-3)-36=0



We calculate terms in parentheses: -(4(x-4)-3), so:

4(x-4)-3

We multiply parentheses

4x-16-3

We add all the numbers together, and all the variables

4x-19

Back to the equation:

-(4x-19)



We get rid of parentheses

6x-4x+19-36=0

We add all the numbers together, and all the variables

2x-17=0

We move all terms containing x to the left, all other terms to the right

2x=17

x=17/2

x=8+1/2

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